In CE, configuration if the voltage drop across is a 5 kilo ohm resistor connected in the collector circuit is 5V find the value of the Ib when B =50
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Answer:
ib=2*10^-5
Explanation:
collector indicates outputvoltage
so ic=vc/rc=5\5*10^3
ic=10^-3
the B=IC\IB
50=10^-3\IB
ib=2*10^-5
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