in certain code rope is written as $3%6 and rite is written as $4#6. how is port written in the code ?
Himanshu121555:
as we know rope =$3%6 and rite =$4#6 then port =%3$@
Answers
Answered by
12
Hey there !
Given, ROPE = $3%6 .
From here , R = $ , O = 3 , P = % , E = 6 .
RITE = $4#6
R = $ , I = 4 , T = # , E = 6 .
Now ,Code for Port :-
P = %
O = 3
R = $
T = #
So ,PORT = %3$#
Given, ROPE = $3%6 .
From here , R = $ , O = 3 , P = % , E = 6 .
RITE = $4#6
R = $ , I = 4 , T = # , E = 6 .
Now ,Code for Port :-
P = %
O = 3
R = $
T = #
So ,PORT = %3$#
Answered by
8
Hello!
We know that rope is written as $3%6.
From this, p is %, o is 3 and r is $.
Also given is rite is written as %4#6.
From this, t is 6.
So, port is written as %3$6.
I hope it is clear.
We know that rope is written as $3%6.
From this, p is %, o is 3 and r is $.
Also given is rite is written as %4#6.
From this, t is 6.
So, port is written as %3$6.
I hope it is clear.
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