Physics, asked by yashingole, 11 months ago

In CGS system the magnitude of the force is 100 dynes. In
another system where the fundamental physical quantities
are kilogram, metre and minute, the magnitude of the
force is
Nm²/kg
(a) 0.036
(b) 0.36
(c) 3.6
(d) 36

Answers

Answered by Anonymous

let the value of force in another system where the fundamental physical quantities are kg,meter,minute be x

then ,using the formula : N1 U1=N2 U2,

the dimensional formula of force = MLT^(-2)

100dynes/x = (g/kg)*(cm/m)* [ (seconds/minute)^(-2) ]

hence,

100/x= (g/1000g)*(cm/100cm)* [(second/60seconds) ]^-2

100/x = 10^(-3)* 10^(-2)* 1/60*60 {since 1kg = 1000g,1 m=100cm,1minute=60 seconds and here 60*60 because of square of time in denominator

solving we get, x=3.6

Answered by shibba20

Answer:

option c(3.6) is the correct answer

Explanation:

by solving

100/x=10^-3*10^-2*1/60*60

100/x=10^-5*1/3600

x=360000/10^-5

x=3.6

Hope it helps you ♥

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