In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J)
Answers
ɪɴ ᴄʜᴀɴɢɪɴɢ ᴛʜᴇ sᴛᴀᴛᴇ ᴏғ ᴀ ɢᴀs ᴀᴅɪᴀʙᴀᴛɪᴄᴀʟʟʏ ғʀᴏᴍ ᴀɴ ᴇǫᴜɪʟɪʙʀɪᴜᴍ sᴛᴀᴛᴇ ᴀ ᴛᴏ ᴀɴᴏᴛʜᴇʀ ᴇǫᴜɪʟɪʙʀɪᴜᴍ sᴛᴀᴛᴇ ʙ, ᴀɴ ᴀᴍᴏᴜɴᴛ ᴏғ ᴡᴏʀᴋ ᴇǫᴜᴀʟ ᴛᴏ 22.3 ᴊ ɪs ᴅᴏɴᴇ ᴏɴ ᴛʜᴇ sʏsᴛᴇᴍ. ɪғ ᴛʜᴇ ɢᴀs ɪs ᴛᴀᴋᴇɴ ғʀᴏᴍ sᴛᴀᴛᴇ ᴀ ᴛᴏ ʙ ᴠɪᴀ ᴀ ᴘʀᴏᴄᴇss ɪɴ ᴡʜɪᴄʜ ᴛʜᴇ ɴᴇᴛ ʜᴇᴀᴛ ᴀʙsᴏʀʙᴇᴅ ʙʏ ᴛʜᴇ sʏsᴛᴇᴍ ɪs 9.35ᴄᴀʟ, ʜᴏᴡ ᴍᴜᴄʜ ɪs ᴛʜᴇ ɴᴇᴛ ᴡᴏʀᴋ ᴅᴏɴᴇ ʙʏ ᴛʜᴇ sʏsᴛᴇᴍ ɪɴ ᴛʜᴇ ʟᴀᴛᴛᴇʀ ᴄᴀsᴇ? (ᴛᴀᴋᴇ 1 ᴄᴀʟ =4.19 ᴊ)
The work done (W) on the system while the gas changes from state A to state B is 22.3J.
⠀⠀⠀⠀⠀⠀⠀⠀ᴛʜᴇʀᴇғᴏʀᴇ , ᴛʜɪs ɪs ᴀɴ ᴀᴅɪᴀʙᴀᴛɪᴄ ᴘʀᴏᴄᴇss
Hence, change in heat is zero.
(Since the work is done on the system)
From the first law of thermodynamics, wehave↴
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Where ,
∆U= Change in the intemal energy of the gas
When the gas goes from state A to state B via a process, the net heat absorbed by the system is ↴
Heat absorbed ;
⠀⠀⠀⠀⠀⠀
⠀⠀
Answer:
Refer The Attachments Sis / Bro ....
