Math, asked by annikasharma2001, 7 months ago

In Chebyshev digital IIR filter using impulse invariant transformation  pass band edge gain 0.9,stopband edge gain 0.24 ,pass band edge analog cut off frequency 0.7854 π rad/sec, stop band edge analog cut off frequency1.5708 π rad/sec give N1(order of the filter)​

Answers

Answered by nehahidayath2005
0
1,5708 + 0.24 multiplied by 12
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