Question

In chemical reaction 10.6 g of Na2CO3 reacted with 12g ethanoic acid, the products obtained were 4.4g of CO2, 16.4g of sodium ethonoate and 1.8g of water. (a) Write the word equation, clearly showing the products and reactants as give above. (b) Also show that this data is in agreement with the low of conservation of mass.

Answer 1

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that the observations are in agreement with the law of conservation of mass. Sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water

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Answer 2

For a: The balanced chemical equation is $Na_2CO_3+2CH_3COOH\rightarrow 2CH_3COONa+H_2O+CO_2$

For b : The given data is in agreement with the law of conservation of mass.

Explanation:

• For a:

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the reaction of sodium carbonate and ethanoic acid follows:

$Na_2CO_3+2CH_3COOH\rightarrow 2CH_3COONa+H_2O+CO_2$

• For b:

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

We are given:

Mass of sodium carbonate = 10.6 g

Mass of ethanoic acid = 12 g

Mass of sodium ethanoate = 16.4 g

Mass of carbon dioxide = 4.4 g

Mass of water = 1.8 g

Total mass on the reactant side = [10.6 + 12] = 22.6 g

Total mass on the product side = [16.4 + 4.4 + 1.8] = 22.6 g

As, total mass on the reactant side = total mass on the product side

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