Biology, asked by umanandamoirangthem1, 5 hours ago

In chicken the allele for a pea vomb Aa is dominant to the allele for a single comb (a) A mother with the genotype Aa And a father with the genotype Aa produces an offspring . What is the percent chance that the offspring will have a single comb

Answers

Answered by PRS73
0

Answer:

boy that's hard

Explanation:

sorry.

hope it helsp soorry

Answered by franktheruler
0

The percent chance that the offspring will have a single comb is 25%.

  • It is given that the chicken allele for pea comb is dominant. While single comb is recessive.
  • Mother has the genotype of Aa. Father has the genotype of Aa. (Both are heterogeneous dominant.)
  • The genotype of the cross between the mother and father can be found out by filling the Punnett square as follows-

      A        a

A     AA      Aa

a      Aa      aa

  • As seen from the above diagram, the genotypic ratio is - AA : Aa : aa = 1 : 2 : 1.
  • The heterogeneous genotype will show the dominant trait.
  • Hene, the phenotypic ratio will be - pea comb : single comb = 3 : 1
  • Thus, 25% of offspring will have a single comb.

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