Question

In circle ab is a diameter of circle C is point on a circle Ac =Bc = 3underroot2 then radius =

Answer 1

Answer:

3 cm

Step-by-step explanation:

AC = BC

$= 3 \sqrt{2} \: cm$

L ACB = 90° (Degree Measure Theorem)

In Triangle ABC, (By Pythagoras Theorem)

${ab}^{2} = {ac}^{2} + {bc}^{2} \\ {ab}^{2} = {(3 \sqrt{2}) }^{2} + {(3 \sqrt{2}) }^{2} \\ {ab}^{2} = 18 + 18 \\ {ab}^{2} = 36 \\ ab = \sqrt{36} \\ ab = 6 \: cm$

$diameter = ab = 6 \: cm \\ radius = 3 \: cm$

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Answer 2

Answer:

r = 3 cm

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