Question

In circle chord AB||tangent DE . C is the point of contact.Prove that Ac=Bc

Answer 1

Answer:

join AC and BC.

OC IS perpendicular to DE.

as AB is parelell to DE, OF is perpendicular to AB⇒AF=BF

In ΔACF ΔBCF

angle F=90

AF=BF

CF=CF

so,ΔACF≅ΔBCF by RHS c.c

by cpct, AC=BC

HP