Question

In circle if radius 10cm,find the length of a chord which is at a distance of 5cm from its center.

Answer 1

hope this helps you

Answer 2

Solution :-

Let O be the center of the circle and AB be the chord of the circle 

Length of OC = 5 cm

Radius of the circle OA = 10 cm

Let OCA be a delta in the given circle. 

By using Pythagoras Theorem -

(OA)² = (AC)² + (OC)²

(10)² = (AC)² + (5)²

100 = (AC)² + 25

(AC)² = 100 - 25

(AC)² = 25cm

AC = √75

AC = 8.66 cm

As we know that the perpendicular from the center to chord bisects the chord.

Therefore, AC = BC = 8.66 cm

Therefore, the length of chord is 8.66 + 8.66

= 17.32 cm

Answer.