In circle o is the center of circle. The angle by the arc bcd at the center is 140 bc is produced to p. Find angle dcp
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in triangle dbo,
do=bo
angle bdo=angle dbo=180-140/2=20
<dcp=<dbp=20. (angle on same segment)
do=bo
angle bdo=angle dbo=180-140/2=20
<dcp=<dbp=20. (angle on same segment)
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