In circle (O, r), AB and CD are two equal chords. If angle AOB = 60°, then find angle COD.
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Step-by-step explanation:
Since AB=CD (equal chords) so, their distance from centre must le equal
So, OP=OQ
Now, In △POQ
(1) ∠OPQ=∠OQP
(2) ∠OPQ+∠OQP+∠POQ=180
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⇒2∠OPQ+150
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=180
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⇒∠OPQ=15
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Also, ∵P is midpoint of AB
OP⊥AB⇒∠APO=90
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Now, ∠APQ=∠APO−∠OPQ=90
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−15
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=75
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