Question

In circle (O, r) AB is a chord. If angle AOB = 90 and radius is 6cm then find the length of AB.

​

Answer 1

Answer:

In triangle AOB

In triangle AOBangle O is 90°

In triangle AOBangle O is 90° AB^2 = AO ^2 + OB^2

In triangle AOBangle O is 90° AB^2 = AO ^2 + OB^2 =6^2 + 6^2

In triangle AOBangle O is 90° AB^2 = AO ^2 + OB^2 =6^2 + 6^2 =36 + 36

In triangle AOBangle O is 90° AB^2 = AO ^2 + OB^2 =6^2 + 6^2 =36 + 36 =92

In triangle AOBangle O is 90° AB^2 = AO ^2 + OB^2 =6^2 + 6^2 =36 + 36 =92AB = √92 cm