In circle with centre O angle QPR is equal to 70. measure of arc PYR is equal to 160. find measure of angle PQR, QOR & measure of arcQXR
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Answer:
Explanation:
For angle QPR=70, m(arc PYR) =160,
m(arc QXR) = 140, angle QOR=140, angle PQR = 80.
Given,
∠QPR =70°
m(arc PYR)= 160
formula,
∠ = 1/2 m(arc PYR)
Now,
m(arc QXR)
∠QPR = 1/2 m( arc QXR)
70 = 1/2 m( arc QXR)
∴m( arc QXR) =140°
Now,
∠QOR
using the properties of triangle, we have,
∠QOR=2∠QPR
=2*70
=140°
Now,
∠PQR
∠PQR = 1/2 m(arc PYR)
=1/2 * 160
=80
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