In circuit R=8ohm P=16w find I
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As P=I^2xR
the current I is 1.414 Amperes.
the current I is 1.414 Amperes.
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power =V×I
voltage= I×R
power= ( I×R)I
power = I²R
given values
R=8ohm P=16w
I²=P/R
I=√P/R
= √(16/8)
I=√2. (√2=1.414)
I=1.414 amp
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voltage= I×R
power= ( I×R)I
power = I²R
given values
R=8ohm P=16w
I²=P/R
I=√P/R
= √(16/8)
I=√2. (√2=1.414)
I=1.414 amp
if u like it please mark as brilliant
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