In circuit shown the total current supplies by battery is
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Explanation:
Here equivalent resistance of the circuit
R
1
1
⇒(
6
1
+
3
1
)Ω⇒
R
1
1
=(
6
1+2
)Ω⇒R
1
=3Ω
Resistance R=
(3Ω+3Ω)
1
+
(3)
1
R
1
=(
6Ω
1
)+(
3
1
)
R
1
=(
6Ω
1
)+(
3
1
)
R
1
=3Ω
I=
3Ω
6V
=2A
solution
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