Question

In circular coil when number of turns are doubled the resistance become

Answer 1

The magnetic field at the center of a coil of radius R and n turns, carrying an electric current I ( per turn) is given by

B=(uo/4 pi) (2 pi)(nI/R)……………………..(1)

Here, uo = permeability of vacuum= (4 pi)x10^-7 TmA^-1.

From equation (1), we read that

when current(I) and number of turns (n) are doubled, B becomes 4B, but doubling the radius R will make the final field twice the original field.

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Answer 2

In circular coil when number of turns are doubled the resistance become 4 times