Question

in class 9th examinations of a school 98 boys and 46 girls appeared The mean marks of the boys was found to be 60% and date of the girls was 40% determine their average marks in percent of the school


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Answer 1

Answer:$\frac{965}{18}$%

Step-by-step explanation:

Let exam be of 100 marks

Therefore mean of boys marks=60 marks

Therefore total marks earned by boys = (60*98)marks=5880 marks

Therefore mean of boys marks=40 marks

Therefore total marks earned by girls = (40*46)marks=1840 marks

Therefore total marks earned =5880+1840=7720 marks

Therefore total marks that can be earned = (98+46)100=14400marks

average marks percent =$\frac{Total Marks Earned}{Total Marks That Can Be Earned}*100 =\frac{7720}{14400} *100=\frac{193}{360} *100=\frac{193}{18} *5=\frac{193*5}{18}=\frac{965}{18}$ %