Question

In climbing a 21 m long round pole, a monkey climbs 6 m in the first minute and slips 3 m in the next minute. What time (in minutes) the monkey would take to reach the top of the pole?
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Answer 1

Answer:

11

Net distance travelled by monkey in 2 min = 3 m

∴∴ In 10 min, distance travelled (climbed) = 15 m

As, it is given in the question that in first minute it climbs 6 m and in other minute it slips down 3 m.

And this happens alternately.

Hence, monkey will travel remaining 6 m in next minute.

∴∴ Total time taken = (10 + 1) = 11 min

Answer 2

Pleae mark as brainliest!

Answer:

$11$

Step-by-step explanation:

This is the height of the monkey for each minute, starting at $0$ minute:

$0,6,3,9,6,12,9,15,12,18,15,21$

We can see that it took $11$ minutes.