IN cm
D
А
11, th the adjoining figure, ABCD is a square grassy lawn of area
729 m² A path of uniform width runs all around it. If the area of
the path is 295 m, find
(1) the length of the boundary of the square field enclosing
the lawn and the path
(ii) the width of the path
Answers
Answer:
Given
Area of square ABCD=729m
2
So, its side =
729
=27m
Let's take the width of path =x m
Then
Side of out field =27+x+x=(27+2x)
and area of square PQRS=(27+2x)
2
m
2
Now
Area of PQRS - Area of ABCD = Area of path
⇒(27+2x)
2
m
2
−729m
2
=295m
2
⇒729+4x
2
+108x−729=295
⇒4x
2
+108x−295=0
By using the quadratic formula, we have
a=4,b=108,c=−295
⇒x=
8
−108±
(108)
2
−4×(4)×(−295)
=
8
−108±
11664+4720
=
8
−108±128
=
8
20
=2.5
Hence, Width of the path =2.5m
Now side of square field PQRS=27+2x=(27+2×2.5)m=32m
Therefore,
Length of boundary =4×side=32×4=128m
Step-by-step explanation:
Hope it will help you
follow me guys
☆Bio Diversity of india?explain.
☆India is one of the mega biodiversity centres in the world and has two of the world's 18 'biodiversity hotspots' located in the Western Ghats and in the Eastern Himalayas (Myers 1999). The forest cover in these areas is very dense and diverse and of pristine beauty, and incredible biodiversity.