Math, asked by paridhalla35, 9 months ago

in colony of Delhi 10% of dogs died from a certain disease and 15% of remaining caused by MCD if number of dogs left now is 6120 what was the original number of dogs before that disease​

Answers

Answered by karansingla760
10

Step-by-step explanation:

percentage of dogs caused by MCD = 15%×(100-10)=15%×90=13.5%

total dogs=6120×100/(100-10-13.5)

= 6120× 100/76.5

= 8000 dogs

Answered by FelisFelis
1

The original number of dogs before the disease are 8000.

Step-by-step explanation:

Consider the provided information.

Let x represents the number of dogs.

It is given that 10% of dogs died.

10% can be written as 0.1.

That means remaining Dogs are: 1-0.1 = 0.9x.

Out of 0.9x dogs, 15% of the remaining caught by M.C.D.

That means out of 0.9x dogs 85% not caught by M.C.D.

85% can be written as: 0.85

Thus, 0.9x × 0.85 = 0.765x

The number of dogs left is 6120.

Therefore,

0.765x = 6120

x = 8000

Hence, the original number of dogs before the disease are 8000.

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