In complex number (1+2i)(-2+i) the value of real and imaginary part is
Answers
Answer:
real part = - 4
imaginary part = - 3
Step-by-step explanation:
⇒ (1 + 2i)(-2 + i)
⇒ -2 + i - 4i + 2i²
⇒ -2 - 3i + 2(-1) [i² = - 1]
⇒ -2 - 3i - 2
⇒ - 4 - 3i
∴ Re(-4 - 3i) = - 4
Im(-4 -3i) = - 3
Given:
A number in the complex form (1+2i)(-2+i).
To Find:
The real and imaginary part after simplifying the equation is?
Solution:
The given number can be solved using the concepts of complex numbers.
1. The standard form of a complex number is a + ib.
2. The given complex form is (1+2i)(-2+i).
=> Simplify the above form,
=> 1*(-2) + 1*i + 2i*(-2) + 2i*i,
=>-2 + i - 4i + 2i², ( The value of i² is -1 )
=> -2 -3i + 2(-1),
=> -2 -3i -2,
=> -4 -3i.
3. a + ib = -4 - 3i,
=> a = real part = -4,
=> b = imaginary part = -3.
Therefore, the real part and the imaginary part of the given number are -4 and -3 respectively.