In component form, vector A is 3i + 6j, and vector B is i + 2j. What is the scalar product of these vectors?
Answers
Answered by
8
Answer:
A.B=(3I+6j).(I+2j)
= 3ii + 6ij + 6 ij + 12 JJ (ii =JJ=kk =1)(ij=jk=Ki=0)
= 3+ 12
=15
Answered by
3
Given: We have given two vector, A : 3i + 6j, and B : i + 2j.
To find: The scalar product of these vectors ?
Solution:
- So now we have given two vectors, those are:
A = ( 3i + 6j ) and B = ( i + 2j )
- Now we know the formula for scalar or dot product which is:
x(vector) = A(vector) . B(vector)
- Now, dot product of i.i is 1 and j.j is 1 and i.j is 0.
x = A.B
x = ( 3i + 6j ) . ( i + 2j )
x = 3i.i + 3i.2j + 6j.i + 6j.2j
x = 3(1) + 0 + 0 + 12(1)
x = 3 + 12
x = 15 = A.B
Answer:
So the scalar product of the given vectors is 15.
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