Question

in compound a 1.00 gram of Nitrogen Unites with 0.57 gram of oxygen in compound B, 2.0 gram of Nitrogen combines with 2.24 gram of oxygen in compound C 3.00 gram of Nitrogen combines with 5.11 gram of oxygen this result obey the law​

Answer 1

Answer:

Explanation:

=> Here, According to the question

Compound A : 1.00 g N + 0.57 g O₂

Compound B : 2.00 g N + 2.24 g O₂

Compound C : 3.00 g N + 5.11 O₂

So If we fixed the amount of nitrogen (1 g) for all compound then,

Compound A :

1.00 g of N Unites with  0.57 g of O₂

Compound B :

2 g N ------> 2.24 O₂

1 g N -------> ?

= 1 * 2.24 / 2

= 1.12 g O₂

Compound C :

3 g N ------> 5.11 O₂

1 g N -------> ?

= 1 * 5.11 / 3

= 1.70 g O₂

=> Thus, Take in consideration the ratio of oxygen of all three compounds for the fixed amount of Nitrogen, then we get

Ratio of oxygen ≈ 1 : 2 : 3

=> This ratio indicates the law of multiple proportion.

Answer 2

Answer:

Explanation:

It obeys "Law of multiple proportion"