Question

In compound interest of certain sum in rs.496.50 for 3 year at the year at the rate of 10 percentage. Find the sum of money​

Answer 1

Answer: P = 496.50    T = 3      R = 10%

A= 496.50(1+ 10/100) to the power 3

A=  4965/10 x 11/10 x 11/10 x 11/10

A= 1193 x 1331/ 100

A = 15878.83

Therefore, the required sum of money = Rupees 15878.83

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Answer 2

Answer:

let P is 100

c. I. =p(1+r/100)*n

496.50 =100( 1+10/100)*3

496.50 =100 (11/10)*3

496.50 = 100*1331/1000

496.50 = 133.1

Amount =133.1

C.I. =amt. - principle

C.I. 133.1 -100

C.I. = 32.9

A/Q

c.i. =496.50. equation 1

A/m

c.i. =32.9 equation 2

compare 1 and 2

32.9 x =496.50

so

x =15.09

x =16 *100

p =1600