Question

in coordinate geometry
how many formula is there​

Answer 1

$\tt\huge{\blue{Answer:-}}$

All Formulas of Coordinate Geometry

General Form of a Line Ax + By + C = 0

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + c

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)The slope of a Line Using Coordinatesm = Δy/Δx = (y2 − y1)/(x2 − x1)

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)The slope of a Line Using Coordinatesm = Δy/Δx = (y2 − y1)/(x2 − x1)The slope of a Line Using General Equationm = −(A/B)Intercept-Intercept Formx/a + y/b = 1

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)The slope of a Line Using Coordinatesm = Δy/Δx = (y2 − y1)/(x2 − x1)The slope of a Line Using General Equationm = −(A/B)Intercept-Intercept Formx/a + y/b = 1Distance Formula|P1P2| = √[(x2 − x1)2 + (y2 − y1)2]

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)The slope of a Line Using Coordinatesm = Δy/Δx = (y2 − y1)/(x2 − x1)The slope of a Line Using General Equationm = −(A/B)Intercept-Intercept Formx/a + y/b = 1Distance Formula|P1P2| = √[(x2 − x1)2 + (y2 − y1)2]For Parallel Lines,m1 = m2

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)The slope of a Line Using Coordinatesm = Δy/Δx = (y2 − y1)/(x2 − x1)The slope of a Line Using General Equationm = −(A/B)Intercept-Intercept Formx/a + y/b = 1Distance Formula|P1P2| = √[(x2 − x1)2 + (y2 − y1)2]For Parallel Lines,m1 = m2For Perpendicular Lines,m1m2 = -1

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)The slope of a Line Using Coordinatesm = Δy/Δx = (y2 − y1)/(x2 − x1)The slope of a Line Using General Equationm = −(A/B)Intercept-Intercept Formx/a + y/b = 1Distance Formula|P1P2| = √[(x2 − x1)2 + (y2 − y1)2]For Parallel Lines,m1 = m2For Perpendicular Lines,m1m2 = -1Midpoint FormulaM (x, y) = [½(x1 + x2), ½(y1 + y2)]

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)The slope of a Line Using Coordinatesm = Δy/Δx = (y2 − y1)/(x2 − x1)The slope of a Line Using General Equationm = −(A/B)Intercept-Intercept Formx/a + y/b = 1Distance Formula|P1P2| = √[(x2 − x1)2 + (y2 − y1)2]For Parallel Lines,m1 = m2For Perpendicular Lines,m1m2 = -1Midpoint FormulaM (x, y) = [½(x1 + x2), ½(y1 + y2)]Angle Formulatan θ = [(m1 – m2)/ 1 + m1m2]

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)The slope of a Line Using Coordinatesm = Δy/Δx = (y2 − y1)/(x2 − x1)The slope of a Line Using General Equationm = −(A/B)Intercept-Intercept Formx/a + y/b = 1Distance Formula|P1P2| = √[(x2 − x1)2 + (y2 − y1)2]For Parallel Lines,m1 = m2For Perpendicular Lines,m1m2 = -1Midpoint FormulaM (x, y) = [½(x1 + x2), ½(y1 + y2)]Angle Formulatan θ = [(m1 – m2)/ 1 + m1m2]Area of a Triangle Formula½ |x1(y2−y3)+x2(y3–y1)+x3(y1–y2)|

General Form of a Line Ax + By + C = 0Slope Intercept Form of a Liney = mx + cPoint-Slope Formy − y1= m(x − x1)The slope of a Line Using Coordinatesm = Δy/Δx = (y2 − y1)/(x2 − x1)The slope of a Line Using General Equationm = −(A/B)Intercept-Intercept Formx/a + y/b = 1Distance Formula|P1P2| = √[(x2 − x1)2 + (y2 − y1)2]For Parallel Lines,m1 = m2For Perpendicular Lines,m1m2 = -1Midpoint FormulaM (x, y) = [½(x1 + x2), ½(y1 + y2)]Angle Formulatan θ = [(m1 – m2)/ 1 + m1m2]Area of a Triangle Formula½ |x1(y2−y3)+x2(y3–y1)+x3(y1–y2)|Distance from a Point to a Lined = [|Ax0 + By0 + C| / √(A2 + B2)]

Answer 2

Answer:

Coordinate Geometry Formulas Class 10

Here let us have a look at all formula of coordinate geometry Class 10.

Distance Formula

Section Formula

Area of a Triangle

A detailed explanation of coordinate geometry class 10 all formulas are given below.

Coordinate Geometry Class 10 Formulas - Distance Formula

To calculate the distance between two points the distance formula is used. Making a triangle by using the Pythagorean theorem to find the length of the hypotenuse gives the distance formula. The distance between the two points in a triangle is called the hypotenuse.

The distance formula can also be used to calculate the lengths of all the sides of a polygon, the perimeter of polygons on a coordinate plane, the area of polygons, and several other things.

The distance formula is denoted by ‘d’.

Distance Formula Between 2 Points in a 2D Plane:

Consider 2 points P and Q having the 2D coordinates as (x1,y1) and (x2,y2) respectively.

Now the distance between these 2 points in the 2D plane is

d=PQ=(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√

d=PQ=(x2−x1)2+(y2−y1)2