In covering a distance of 40 km Sachin takes 3 hours more than Utkarsh. If Sachin doubles his speed then he would take 1 hour less than Utkarsh. Find their speeds.
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Distance covered, d = 40 km.
Let,
v1 and t1 be Kamlesh’s speed and time of travel.
v2 and t2 be Pankaj’s speed and and time of travel.
t1 = d/v1 = 40/v1
t2 = d/v2 = 40/v2
Kamlesh takes 2 hours more than Pankaj
t1 = t2+2
(40/v1) = (40/v2)+2 ——(1)
If Kamlesh doubles his speed, then he would take 1 hour less than Pankaj.
d/(2v1) = (d/v2)-1
40/(2v1) = (40/v2)-1 ——(2)
Substituting the value of (40/v2) in terms of (40/v1),
40/(2v1) = [(40/v1)-2]-1
v1= 40/6 = 6.66 km/h
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