Question

in cricket match a batsman hiys boundry 6 times out of 30 balls he plays. find the probability thet he did not hit the boundry​

Answer 1

Step-by-step explanation:

In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Find the probability that she did not hit a boundary.

Total number of balls played = 30

Number of times the batswoman hits a boundary 6

.. Number of balls the batswoman does not hit a boundary = 30 - 6

= 24

P(she does not hit a boundary)

Number of balls when she does not hit boundary /Total number of balls played

24/30 =5

Answer 2

Step-by-step explanation:

Total number of hittings of ball = 30 ∴ n(S) = 30. Total number of boundary = 6 Total number of No boundaries = 30 – 6 = 24 ∴ n(E) = 24 Probability of No boundary hits = /in-a-cricket-match-a-batswoman-hits-a-boundary-6-times-out-of-30-balls-she-plays

total number of boundary/ total number of heating ball.

P(E)= n(E)/n(S)

therefore, n(E) = 24/30.