In curvilinear motion particle acceleration vector is
Answers
Answered by
1
Answer:
My textbook mentions that the direction of net instantaneous velocity is along the tangent to the curve. Well, from the polar coordinate system I also know that the net instantaneous velocity has two components: one along the radius of curvature and the other perpendicular to it. But when I sum these two velocities the resultant is not along the tangent to the curve. A simple explanation with an elementary knowledge of vectors would highly be appreciated.
Explanation:
Similar questions