Question

In CuSO4 .5H2O, the percentage of water is (Mass numbers - Cu= 63.5, S=32, O=16, H=1)

Answer 1

Answer:-

36.07 %

Explanation:-

Firstly, let's calculate the molecular mass of CuSO₄.5H₂O:-

= 63.5+32+16×4+5(1×2+16)

= 95.5+64+5(18)

= 159.5+90

= 249.5u

We know that molar mass is the molecular/atomic mass in grams.

Thus, molar mass of CuSO₄.5H₂O is 249.5g.

In CuSO₄.5H₂O, there are 5 moles of water.

We know that the molar mass of water is 18g. Thus , the mass of water in the compound:-

= No of moles×Molar mass

= 18×5

= 90g.

Now, precentage composition of water in

CuSO₄.5H₂O :-

= 90/249.5×100

= 9000/249.5

= 36.07%

Thus, the percentage composition of water in CuSO₄.5H₂O is 36.07%.