Chemistry, asked by DevendraWarghude, 7 months ago

In CuSO4.H2O the percentage of water is .......
(Cu=63.5, S=32, O=16, H=1)

a) 10 %

b) 36 %

c) 60 %

d) 72 %​

Answers

Answered by Alivean
2

Explanation:

Molecular weight of CuSO4.H2O = 63.5 + 32 + 4(16) + 18 = 177.5

Percentage of water = 18/178 × 100 = 10.14 %

Answered by vaibhav20085
1

Answer:

b) 36% is the only correct option I will give you the whole explanation.

Explanation:

The molecular weight of water H

2

O=2(1)+16=18g/mol.

The molecular weight of copper sulphate pentahydrate CuSO

4

.5H

2

O=64+32+4(16)+5(18)=250g/mol.

The percentage of water of crystallization in CuSO

4

.5H

2

O=

250

5×18

×100=36%.

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