In cyclic a PQRS. point T on ray SR. SQRT - 100, then SPQ =?
Answers
Answered by
1
Answer:
In △TPS and △TRQ
∠PST=∠RQT
∠SPQ=∠QRT
[∵ exterior angle of cyclic quadrilateral is equal to the interior opposite angle]
∠T=∠T (common)
∴△TPS−△TRQ (By AA)
Similar questions