Question

In cyclic a PQRS. point T on ray SR. SQRT -100, then SPQ =?​

Answer 1

Given:PQRS is cyclic quadrilateral,

QRT=100°

To find: 1)SRQ 2)SPQ

Solution:1)In PQRS, SRQ+QRT=180°_(linear pair angles)

:.SRQ+100°=180°

:.SRQ=80°

Now,2)SPQ+SRQ=180°_(Opposite angles of cyclic quadrilateral are supplementary)

:.SPQ=180°-80°

:.SPQ=100°

I hope this will helpful to you!!

Thank you!!