In cyclic quadrilaterABCD, measure angleA + measure angleB = 150 and measure angleB + measure angleC = 190. find measure angleD.
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Angle B= 190°-150°= 40°
Angle B+ Angle D= 180° (as sum of opposite angles of cyclic quad. is 180°)
40° + angle d= 180°
angle d= 180°-40°= 140°
Angle B+ Angle D= 180° (as sum of opposite angles of cyclic quad. is 180°)
40° + angle d= 180°
angle d= 180°-40°= 140°
kkumar0123450:
sorry its rough
Answered by
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angle A + angel B +angleC+angle d =360° - 150°-190° =10°
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