In cyclic quadrilateral ABCD angle A = (2x+4) angle B = (y+3) angle C=(2y+10) and angleD=(4x-5) find four angles
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angle A= angle D
2x+4=4x-5
2x-4x=-5-4
-2x=-9
x=-9/-2=9/2
Angle B = angle C
y+3=2y+10
y-2y=10-3
-y=7
y=-7
Now put the value of x and y , u will get the answer
2x+4=4x-5
2x-4x=-5-4
-2x=-9
x=-9/-2=9/2
Angle B = angle C
y+3=2y+10
y-2y=10-3
-y=7
y=-7
Now put the value of x and y , u will get the answer
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