Question

in cyclic quadrilateral ABCD , angle A=70° and angle B+angle c=160 then angle B=?​

Answer 1

Answer:

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A = 70°

B + C = 160°

To find:-

The value of B--

Let , B = x

C = 2x

Then,,

B + C = 160°

x + 2x = 160°

3x = 160°

x = 160°/3

x = 53.3°

Hence the value of B = 53.3°