in cyclic quadrilateral ABCD ,angle ABD=70°and angle BCD=100°.find angle ADB
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Answer:
ANS is 30 hope it helps do rate me up if it is correct
Step-by-step explanation:
DCB+DAB=180
DAB=180-100=80
in triangle ABD
DAB+BDA+ABD =180
BDA=180-(80+70)
=180-150
=30
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