Question

In cyclic quadrilateral ABCD angle ACB=40 DAB=60 find DBA​

Answer 1

Answer:

angle ACB = angle ADB (angle in the same segment are equal)

Therefore, angle ADB = 40° ( Since angle ACB = 40°)

  Now,in Triangle ABD,

    angle ABD + angle ADB + angle DAB = 180° (Angle Sum Property)

   angle ABD + 40° + 60° = 180°

   angle ABD + 100° = 180°

   Thus, angle ABD = 180° - 100°

                angle ABD = 80°

Hope it helps.......... :

Explanation: