Question

In cyclic quadrilateral ABCD diagonal AC and BD intersect at P If angle DBC=70degree and angleBAC =30 degree then find angle BCD

Answer 1

Answer:

I think it is 80°

Sorry if not correct

Thanks

Answer 2

∠BCD = 80°

Step-by-step explanation:

∠DAC = ∠DBC  ( angle by same chord  DC)

=> ∠DAC =  70°

∠BAC =  30°

∠DAB = ∠DAC  + ∠BAC  = 70° + 30°

=> ∠DAB = 100°

∠DAB +  ∠BCD = 180° ( sum of opposte angle sof cyclic quadrilateral)

=> 100° +  ∠BCD = 180°

=> ∠BCD = 80°

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