Question

In cyclic quadrilateral ABCD, diagonals AC and BD intersect
at P. If Z DBC = 70° and Z BAC = 30°, then find BCD.​

Answer 1

Step-by-step explanation:

, refers to the attachment

Answer 2

Answer:

Step-by-step explanation:

hey mate/////

here is ur answer

 The region between a chord and either of its arcs is called a segment the circle.

Angles in the same segment of a circle are equal.

For chord CD,

We know, that Angles in same segment are equal.

∠CBD = ∠CAD

∠CAD = 70°

∠BAD = ∠BAC + ∠CAD = 30° + 70° = 100°

∠BCD+∠BAD= 180°       

 (Opposite angles of a cyclic quadrilateral)

 ∠BCD + 100° = 180°

∠BCD = 180° - 100°

∠BCD =80°

In ΔABC

AB = BC (given)

∠BCA = ∠CAB (Angles opposite to equal sides of a triangle)

∠BCA = 30°

also, ∠BCD = 80°

∠BCA + ∠ACD = 80°

30° + ∠ACD = 80°

∠ACD = 50°

∠ECD = 50°

Hence, ∠BCD = 80° & ∠ECD = 50°

#answerwithquality and #BAL