Question

In cyclic quadrilateral ABCD the bisector of opposite angles A and C meet the circle P and Q respectively prove that PQ is diameter of a circle (hint draw a segment PC)

Answer 1

Answer:

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Step-by-step explanation:

• If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle.
• Thinking Process
• Use the property of cyclic quardrilateral, the sum of opposite angles of cyclic quadrilateral is supplementary. Further, simplify it to prove the

Answer 2

Answer:

Given, ABCD is a cyclic quadrilateral.

DP and QB are the bisectors of ∠D and ∠B, respectively.

To prove PQ is the diameter of a circle.

Construction Join QD and QC.