In Δ , D and E are points on the sides AB and AC respectively. Show that DE ∥ BC if AB = 10.8cm, BD = 4.5cm, AC = 4.8cm and AE = 2.8cm
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Given : D and E are the points on sides AB and AC. AB = 10.8 cm, BD = 4.5 cm, AC = 4.8 cm, and AE = 2.8 cm
To prove : DE || BC.
AD = AB – DB
AD = 10.8 – 4.5
AD = 6.3 cm
EC = AC – AE
EC = 4.8 – 2.8
EC = 2 cm
In ∆ABC,
AD / DB = 6.3/4.5 = 7/5 = 1.4
And, AE/EC = 2.8 /2.0 = 1.4
so, AD / DB = AE/EC
Hence, DE || BC.
[By Converse of basic proportionality theorem]
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