In d fig. ST||RQ , PS =3cm and SR=4cm. find the ratio of the area of ∆PST to the area of ∆PRQ.
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area of triangles ratio would be the ratio of corresponding sides
ps=3cm,pr=3+4=7cm
then ratio of areas=9:49
ps=3cm,pr=3+4=7cm
then ratio of areas=9:49
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the ratio of the area of triangle pst :triangle prq=2:1(mid point theorem).a line joining the mid points of two sides will be equal to 1/2 area of the third side.
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