in DABC bisector of DA meets Bc at point D if AB=6cm AC=5cm and BD=3cm then BC= ____ cm
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we can see that ∠BAC∠BAC is bisected by AD where AD touches BC at D. BC=BD+DCBC=BD+DCwhere, BC=3cmBC=3cm. We also have the values of adjacent sides AB=6cmAB=6cmand AC=5cmAC=5cm.
These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:
ABBD=ACDCABBD=ACDC
⇒DC=AC∗BDAB=5∗36=2.5cm
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