Question

In DABC, LB 390° AB 3 (2+1) cm
and BC = (a + L) cm. If the area of
the DABC is 60 cm2, find its
Perimeter​

Answer 1

Answer:

We assume ABCD be the quadrilateral having sides AB, BC, CD, DA and ∠ACB = 90∘.

We take a diagonal AC, where AC divides ABCD into two triangles ΔACB and ΔADC

Since ∆ACB is right angled at C, we have

AC = 15 cm; AB = 17 cm

AB2 = AC2 + BC2

Area of right angled triangle ABC, say A1 is given by

, where,

Base = BC = 8 cm; Height = AC = 15 cm

Area of triangle ADC, say A2 having sides a, b, c and s as semi-perimeter is given by

, where

a = AD = 9 cm; b = DC = 12 cm; c = AC = 15 cm

Area of quadrilateral ABCD, say A

A = Area of ∆ACB + Area of ∆ADC

Perimeter of quadrilateral ABCD, say P

hope it helps you....