in December the minimum temperature in Srinagar happens to be 35.6 degrees Fahrenheit what is temperature in Celsius scale
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Answered by
2
By formula
C= 5/9(F- 32)
Given F = 35.6
C= 5/9(35.6 - 32.0)
C= 5/9(3.6)
C= 5/9(36/10)
C= 2
C= 5/9(F- 32)
Given F = 35.6
C= 5/9(35.6 - 32.0)
C= 5/9(3.6)
C= 5/9(36/10)
C= 2
neha9992:
thanks
Answered by
0
2 degree Celsius
C=5÷9×(F-32)=(3.6×5)÷9
C=5÷9×(F-32)=(3.6×5)÷9
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