In decimal numerals, if 36 is added to a certain two-digit number, the result is the number with the digits reversed. The units' digit is the one more than twice the tens' digit. What is the number?
please give answer of this
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Step-by-step explanation:
let the digits of the 2-digit number be
unit digit=x
tens place digit=y
number=10y+x. 1}
according to the question
x=2y+1
so
number=10y+(2y+1) 2}
according to the question
{10y+(2y+1)} +36= 10(2y+1)+y. 3}
=>12y+37=20y+10+y
=>12y+37=21y+10
=>-10+37=21y+12y
=>37-10=33y
=>27=33y
=>y=27 =9
33. 11
I'm not sure if this is the right value for y ...
please just form the equation 1} and substitute this value and check if this is correct..
hope this helps.
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