in ∆ DEF, G is Midpoint of EF , DG is produced up to H so that DG = GH prove that ∆ DEG ∆ GFH are congruent
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For triangle DEF, let the angles are x,y and
then x + y + z = 180°
Add these three equations, we get
∠DFP + ∠EDQ + ∠FER = 540° −(x + y + z)
- Hence, ∠DFP + ∠EDQ + ∠FER = 360°
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