Question

In ΔDEF, the measure of ∠F=90°, the measure of ∠D=69°, and FD = 64 feet. Find the length of DE to the nearest tenth of a foot.

Answer 1

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Given:-

∆DEF with <F-90°, the measure of <D=69°, and FD = 64 feet, since one of the angles of the triangle is 90°, the triangle is a right angled triangle as shown in the attachment.

• Using SOH, CAH, TOA to get the unknown EF.

Since <D is opposite to side EF, EF will be the opposite while side DE will be the hypotenuse.

Based on SOH:

Sin<D = Opposite/Hypotenuse

Sin<D = EF/FD

Sin 69° = EF/64

DE = 64 sin 69°

DE = 59.7 feet to the nearest tenth of a foot

Answer 2

Answer: 178.6

Step-by-step explanation: