In deriving the single slit diffraction pattern, it was stated that the intensity is zero at angles of nλ/a. Justify this by suitably dividing the slit to bring out the cancellation.
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In deriving the single slit diffraction pattern, it was stated that the intensity is zero at angles of nλ/a. Justify this by suitably dividing the slit to bring out the cancellation.
solution : Let width of single slit is a is divided into n smaller slits. if a' is the width of each one of the smaller slits, a' = a/n. ....(1)
now for the single slit to produce zero intensity, each one of the smaller slits should also produce zero intensity.
But this is possible only if,
angle, α = λ/a'
or, α = λ/(a/n) [ from equation (1), ]
or, α = nλ/a
hence, it is clear that, in deriving the single slit diffraction pattern, it was stated that the intensity is zero at angles of .
Answer:
Explanation:
In deriving the single slit diffraction pattern, it was stated that the intensity is zero at angles of nλ/a. Justify this by suitably dividing the slit to bring out the cancellation.
solution : Let width of single slit is a is divided into n smaller slits. if a' is the width of each one of the smaller slits, a' = a/n. ....(1)
now for the single slit to produce zero intensity, each one of the smaller slits should also produce zero intensity.
But this is possible only if,
angle, α = λ/a'
or, α = λ/(a/n) [ from equation (1), ]
or, α = nλ/a
hence, it is clear that, in deriving the single slit diffraction pattern, it was stated that the intensity is zero at angles of .